15x^2-2=25

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Solution for 15x^2-2=25 equation:



15x^2-2=25
We move all terms to the left:
15x^2-2-(25)=0
We add all the numbers together, and all the variables
15x^2-27=0
a = 15; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·15·(-27)
Δ = 1620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1620}=\sqrt{324*5}=\sqrt{324}*\sqrt{5}=18\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{5}}{2*15}=\frac{0-18\sqrt{5}}{30} =-\frac{18\sqrt{5}}{30} =-\frac{3\sqrt{5}}{5} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{5}}{2*15}=\frac{0+18\sqrt{5}}{30} =\frac{18\sqrt{5}}{30} =\frac{3\sqrt{5}}{5} $

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